document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=111923>Question 111923</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mark uses 1 pt 9 fl oz and then 2 pt 10 fl oz from a container of film developer that holds 3 qt. How much of the developer remains?\r<BR>\n" );
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document.write( "Help please i dont no what to do with this one. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #81675 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=81675\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A quart is 32 fluid oz and a pint is 16 fluid oz.<BR>\n" );
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document.write( "Since Mark starts with 3 quarts, he begins with 3 times 32 fluid oz or 96 fluid oz of developer.<BR>\n" );
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document.write( "First he uses 1 pt 9 fluid oz of developer. Since the pint is 16 fluid oz, he uses 16 plus 9 <BR>\n" );
document.write( "or 25 fluid oz.<BR>\n" );
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document.write( "Next he uses 2 pints plus 10 fluid oz. The 2 pints is 32 fluid oz and the 10 fluid oz makes<BR>\n" );
document.write( "a total of 42 fluid oz used on this second time.<BR>\n" );
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document.write( "So the total that mark uses is 25 fluid oz plus 42 fluid oz for a total of 67 fluid oz.<BR>\n" );
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document.write( "Since he stated with 96 fluid oz and he used 67 fluid oz, he is left with 96 minus 67 <BR>\n" );
document.write( "fluid oz which is 96 - 67 = 29 fluid oz.<BR>\n" );
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document.write( "He is left with 29 fluid oz. But since a pint equals 16 fluid oz, you can say that the<BR>\n" );
document.write( "29 fluid oz that remains is 1 pint plus 13 fluid oz.<BR>\n" );
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document.write( "Hope this helps you to understand the problem.<BR>\n" );
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