document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=111934>Question 111934</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This is a science and medicine.<BR>\n" );
document.write( "A bicyclist rode into the country for 5h. In returning , her speed was 5mi/h faster and the trip took 4h. What was her speed each way?<BR>\n" );
document.write( "Would the answer be 20mi/h and 25mi/h? \r<BR>\n" );
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document.write( "Thank you,<BR>\n" );
document.write( "Barb Neely </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #81674 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=81674\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Your answer is correct. Her speed was 20 mph going into the country and 25 mph during her<BR>\n" );
document.write( "return ride.<BR>\n" );
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document.write( "You can check this as follows: On her way into the country she rode at 20 mph for 5 hours<BR>\n" );
document.write( "so she covered 100 miles. On her return trip she rode at 25 mph and in 4 hours she covered<BR>\n" );
document.write( "25 times 4 = 100 miles. Her two rides covered the same distance ... so the speeds<BR>\n" );
document.write( "are correct.<BR>\n" );
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document.write( "This comes from recognizing that the two distances covered (distance out into the country and<BR>\n" );
document.write( "distance on the return trip) must be the same. So you can use the distance formula of:<BR>\n" );
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document.write( "Distance = speed times time <BR>\n" );
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document.write( "and in equation form this is <BR>\n" );
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document.write( "D = S * T<BR>\n" );
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document.write( "for each leg of the trip. Call R the speed on the outbound trip. Then R + 5 must be the<BR>\n" );
document.write( "speed on the return trip. This means that the distance on the outbound trip is:<BR>\n" );
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document.write( "D = R * 5 = 5R<BR>\n" );
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document.write( "where 5 is the time in hours on the outbound leg. Then the return distance is:<BR>\n" );
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document.write( "D = (R + 5)*4 = 4R + 20 <BR>\n" );
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document.write( "in which R + 5 is the speed on the return trip and 4 is the number of hours spent at<BR>\n" );
document.write( "that speed.<BR>\n" );
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document.write( "Since the two distances are equal, you can set them equal in equation form to get:<BR>\n" );
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document.write( "5R = 4R + 20<BR>\n" );
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document.write( "Subtract 4R from both sides of this equation and it reduces to:<BR>\n" );
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document.write( "R = 20<BR>\n" );
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document.write( "And 20 is the speed in mph for the outbound ride. Therefore 25 mph must be the speed for<BR>\n" );
document.write( "the return leg because is is 5 mph faster than the speed on the outbound leg.<BR>\n" );
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document.write( "Hope this helps. </SPAN>\n" );
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