document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1185865>Question 1185865</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In each pair, decide which question you will you use first to solve for one variable om terms of the other variable. Do that step. Do not solve the linear system. \r<BR>\n" );
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document.write( "a) x + 2y = 5<BR>\n" );
document.write( "   3x + 2y = 6 \r<BR>\n" );
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document.write( "b) 2x + y = 6<BR>\n" );
document.write( "   3x + 2y = 10 \r<BR>\n" );
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document.write( "c) 2x + 5y = 7<BR>\n" );
document.write( "   x - 3y = -2 \r<BR>\n" );
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document.write( "d) 3x - y = 5 <BR>\n" );
document.write( "   7x + 2y = 9\r<BR>\n" );
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document.write( "e) 2x - y = 2<BR>\n" );
document.write( "   4x + y = 16  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #816734 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39618)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=816734\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The questions to choose from or to look for are not made clear.\r<BR>\n" );
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document.write( "a) x + 2y = 5<BR>\n" );
document.write( "3x + 2y = 6<BR>\n" );
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document.write( "Add the opposite of equation 1 to equation 2, which eliminates y, and quickly find the x value.  If you instead want to use substitution to begin, then solve equation 1 for x, and substitute into equation 2.\r<BR>\n" );
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document.write( "b) 2x + y = 6<BR>\n" );
document.write( "3x + 2y = 10<BR>\n" );
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document.write( "Solve equation 1 for y, and substitute this into equation 2; and solve first for value of x from this.\r<BR>\n" );
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document.write( "c) 2x + 5y = 7<BR>\n" );
document.write( "x - 3y = -2<BR>\n" );
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document.write( "You can figure what to do now.\r<BR>\n" );
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document.write( "d) 3x - y = 5<BR>\n" );
document.write( "7x + 2y = 9<BR>\n" );
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document.write( "Take equation 1 and solve y in terms of x; and substitute into equation 2, and ....\r<BR>\n" );
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document.write( "e) 2x - y = 2<BR>\n" );
document.write( "4x + y = 16<BR>\n" );
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document.write( "...! </SPAN>\n" );
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