document.write( "Question 111917: Find the area of a regular pentagon with apothem 15 meters. Show all work to receive credit. \n" ); document.write( "
Algebra.Com's Answer #81673 by edjones(8007)\"\" \"About 
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apothem=r=15 m
\n" ); document.write( "n=5
\n" ); document.write( "beta=180(n-2)/n=180*3/5=108 deg=each interior angle.
\n" ); document.write( "R, the radius of a circumscribed circle bisects each int angle.
\n" ); document.write( "cot(54)=adj/opp
\n" ); document.write( "adj=cot(54)*r=cot(54)*15=10.098...
\n" ); document.write( "10.098...*2=21.796...=base of the triangle and a side of the pentagon
\n" ); document.write( "1/2alt.*base=A
\n" ); document.write( "1/2*15*21.796...=163.472... m^2
\n" ); document.write( "There are 5 triangles in the regular pentagon.
\n" ); document.write( "5*163.472...=817.36...m^2 area of the pentagon.
\n" ); document.write( "Ed
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