document.write( "Question 111917: Find the area of a regular pentagon with apothem 15 meters. Show all work to receive credit. \n" ); document.write( "
Algebra.Com's Answer #81673 by edjones(8007)![]() ![]() You can put this solution on YOUR website! apothem=r=15 m \n" ); document.write( "n=5 \n" ); document.write( "beta=180(n-2)/n=180*3/5=108 deg=each interior angle. \n" ); document.write( "R, the radius of a circumscribed circle bisects each int angle. \n" ); document.write( "cot(54)=adj/opp \n" ); document.write( "adj=cot(54)*r=cot(54)*15=10.098... \n" ); document.write( "10.098...*2=21.796...=base of the triangle and a side of the pentagon \n" ); document.write( "1/2alt.*base=A \n" ); document.write( "1/2*15*21.796...=163.472... m^2 \n" ); document.write( "There are 5 triangles in the regular pentagon. \n" ); document.write( "5*163.472...=817.36...m^2 area of the pentagon. \n" ); document.write( "Ed \n" ); document.write( " \n" ); document.write( " |