document.write( "Question 111936: I need to completely factor 100-x^2y^2 and I came up with (50-xy)(50+xy). Is this correct? \n" ); document.write( "
Algebra.Com's Answer #81672 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
You can always check these by multiplying your answers and to see if they match the original
\n" ); document.write( "given. In this case if you multiply the factors in your answer you will get:
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\n" ); document.write( "2500 + 50xy -50xy - x^2y^2
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\n" ); document.write( "The two middle terms cancel so your answer becomes 2500 - x^2y^2
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\n" ); document.write( "Something is wrong. In this case you took a half of 100 (which is 50) as the first part of your
\n" ); document.write( "factors. You should have taken the square root of 100 (which is 10) so that your answer would
\n" ); document.write( "be (10 - xy)(10 + xy). If you multiply these two factors you get:
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\n" ); document.write( "100 + 10xy - 10xy - x^2y^2
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\n" ); document.write( "and when the two middle terms of this answer are canceled out because they are equal but
\n" ); document.write( "have opposite signs, you are left with:
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\n" ); document.write( "100 - x^2y^2
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\n" ); document.write( "which is the same form as you were originally given ... so it does check.
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\n" ); document.write( "Hope this helps.
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