document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1185739>Question 1185739</A>: <I><SPAN STYLE=\"word-break: break-all;\"> SOLVE USING GEOMETRIC CONSTRUCTION.<BR>\n" );
document.write( "FIND THE EQUATION OF THE CIRCLE TANGET TO 3X+4Y-15=0 AT P1(1,3) AND PASSING THROUGH P2(6,3) AND P3(O,5)\r<BR>\n" );
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document.write( "SOLUTION AND CIRCLE TANGENT<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #816678 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=816678\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SOLVE USING GEOMETRIC CONSTRUCTION.<BR>\n" );
document.write( "FIND THE EQUATION OF THE CIRCLE TANGET TO 3X+4Y-15=0 AT P1(1,3) AND PASSING THROUGH P2(6,3) AND P3(O,5)<BR>\n" );
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document.write( "Given 3 points: A(1,3), B(6,3) and C(0,5)<BR>\n" );
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document.write( "Find the center of the circle;<BR>\n" );
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document.write( "Step 1, find the perpendicular bisector of AB and of BC<BR>\n" );
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document.write( "Midpoint of AB is (3.5,3)<BR>\n" );
document.write( "Perp bisector is x = 3.5<BR>\n" );
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document.write( "Midpoint of BC is (3,4)<BR>\n" );
document.write( "Slope of BC is -1/3<BR>\n" );
document.write( "Perp bisector is y = 3x - 5<BR>\n" );
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document.write( "The center is the intersection of the 2 bisectors @ (3.5,5.5)<BR>\n" );
document.write( "Radius is the distance from the center to any point = sqrt(12.5)<BR>\n" );
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document.write( "The circle passes thru the 3 points, but is NOT tangent to the given line.<BR>\n" );
document.write( "No such circle is possible.<BR>\n" );
document.write( "An ellipse can be found to fit, or one of the 3 points eliminated for a circle.\r<BR>\n" );
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