document.write( "Question 1185639: A gardener buys a package of seeds. Ninety percent of seeds
\n" ); document.write( "of this type germinate. The gardener plants 90 seeds.
\n" ); document.write( "Approximate the probability that fewer than 72 seeds
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\n" ); document.write( "\n" ); document.write( "a. 0.9996
\n" ); document.write( "b.0.9998
\n" ); document.write( "c.0.0004
\n" ); document.write( "d.0.0002
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Algebra.Com's Answer #816674 by robertb(5830)\"\" \"About 
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The original distribution is B(90, 0.90). Use the normal distribution N(np, npq) = N(81, 8.1) to approximate the probability \"P%28X%5BB%5D+%3C+72%29\".
\n" ); document.write( "(Both np and n(1-p) are greater than 5, so we can do the normal approximation.)\r
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\n" ); document.write( "\n" ); document.write( "The answer is thus (c).
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