document.write( "Question 1185815: Make a rectangle with an area which is at most 35cm, where the width is 2cm more than its length Find the possible dimensions of the rectangle. (with solution) \n" ); document.write( "

Algebra.Com's Answer #816668 by greenestamps(13200) $\"\"$ $\"About$

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\n" ); document.write( "x = length
\n" ); document.write( "x+2 = width

\n" ); document.write( "The area (length times width) is at most 35 cm^2 (not 35 cm):

\n" ); document.write( " $\"x%28x%2B2%29%3C=35\"$
\n" ); document.write( " $\"x%5E2%2B2x%3C=35\"$
\n" ); document.write( " $\"x%5E2%2B2x-35%3C=0\"$
\n" ); document.write( " $\"%28x%2B7%29%28x-5%29%3C=+0\"$

\n" ); document.write( " $\"-7%3C=x%3C=5\"$

\n" ); document.write( "Obviously negative values make no sense in the problem. So

\n" ); document.write( "ANSWER: The length x is less than 5 (and not negative)

\n" ); document.write( " \n" ); document.write( "

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