document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1185591>Question 1185591</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One side and the altitude of a rhombus measure 120 m and 90 m respectively.<BR>\n" );
document.write( "a) Find the area of the rhombus.<BR>\n" );
document.write( "b) Find the smaller interior angle of the rhombus.<BR>\n" );
document.write( "c) Find the length of the shorter diagonal.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #816655 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=816655\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a)  Just like any parallelogram, the area will be base x height = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=120+%2A+90+m%5E2+=+%2210%2C800%22+m%5E2 ALIGN=MIDDLE  ALT=\"120+%2A+90+m%5E2+=+%2210%2C800%22+m%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "b) The smaller interior angle of the rhombus can be obtained from <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sin%28theta%29+=+90%2F120+=+3%2F4 ALIGN=MIDDLE  ALT=\"sin%28theta%29+=+90%2F120+=+3%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  This would give <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=48.59%5E0 ALIGN=MIDDLE  ALT=\"48.59%5E0\"   DISABLED_style= \"max-width:90%; height:auto;\" >, to 2 d.p.\r<BR>\n" );
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document.write( "c)  The length of the shorter diagonal can be obtained from getting the value of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2alpha ALIGN=MIDDLE  ALT=\"2alpha\"   DISABLED_style= \"max-width:90%; height:auto;\" > from <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=alpha%2F120+=+sin%28theta%2F2%29+=+sin%2848.59%2F2%29 ALIGN=MIDDLE  ALT=\"alpha%2F120+=+sin%28theta%2F2%29+=+sin%2848.59%2F2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  <BR>\n" );
document.write( "Therefore the length of the shorter diagonal is 98.74 meters, to 2 d.p. </SPAN>\n" );
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