document.write( "Question 111919This question is from textbook Beginning Algebra
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\n" ); document.write( "\n" ); document.write( "2x + 3y = 6\r
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Algebra.Com's Answer #81661 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Graphing Linear Equations

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\n" ); document.write( " \"2%2Ax%2B3%2Ay=6\"Start with the given equation
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\n" ); document.write( " \"3%2Ay=6-2%2Ax\" Subtract \"2%2Ax\" from both sides
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\n" ); document.write( " \"y=%281%2F3%29%286-2%2Ax%29\" Multiply both sides by \"1%2F3\"
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\n" ); document.write( " \"y=%281%2F3%29%286%29-%281%2F3%29%282%29x%29\" Distribute \"1%2F3\"
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\n" ); document.write( " \"y=6%2F3-%282%2F3%29x\" Multiply
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\n" ); document.write( " \"y=%28-2%2F3%29%2Ax%2B6%2F3\" Rearrange the terms
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\n" ); document.write( " \"y=%28-2%2F3%29%2Ax%2B2\" Reduce any fractions
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\n" ); document.write( " So the equation is now in slope-intercept form (\"y=mx%2Bb\") where \"m=-2%2F3\" (the slope) and \"b=2\" (the y-intercept)
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\n" ); document.write( " So to graph this equation lets plug in some points
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\n" ); document.write( " Plug in x=-9
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\n" ); document.write( " \"y=%28-2%2F3%29%2A%28-9%29%2B2\"
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\n" ); document.write( " \"y=18%2F3%2B2\" Multiply
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\n" ); document.write( " \"y=24%2F3\" Add
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\n" ); document.write( " \"y=8\" Reduce
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\n" ); document.write( " So here's one point (-9,8)
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\n" ); document.write( " Now lets find another point
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\n" ); document.write( " Plug in x=-6
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\n" ); document.write( " \"y=%28-2%2F3%29%2A%28-6%29%2B2\"
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\n" ); document.write( " \"y=12%2F3%2B2\" Multiply
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\n" ); document.write( " \"y=18%2F3\" Add
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\n" ); document.write( " \"y=6\" Reduce
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\n" ); document.write( " So here's another point (-6,6). Add this to our graph
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\n" ); document.write( " Now draw a line through these points
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\n" ); document.write( " So this is the graph of \"y=%28-2%2F3%29%2Ax%2B2\" through the points (-9,8) and (-6,6)
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\n" ); document.write( " So from the graph we can see that the slope is \"-2%2F3\" (which tells us that in order to go from point to point we have to start at one point and go down -2 units and to the right 3 units to get to the next point), the y-intercept is (0,\"2\")and the x-intercept is (\"3\",0) . So all of this information verifies our graph.
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\n" ); document.write( " We could graph this equation another way. Since \"b=2\" this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,\"2\").
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\n" ); document.write( " So we have one point (0,\"2\")
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\n" ); document.write( " Now since the slope is \"-2%2F3\", this means that in order to go from point to point we can use the slope to do so. So starting at (0,\"2\"), we can go down 2 units
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\n" ); document.write( " and to the right 3 units to get to our next point
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\n" ); document.write( " Now draw a line through those points to graph \"y=%28-2%2F3%29%2Ax%2B2\"
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\n" ); document.write( " So this is the graph of \"y=%28-2%2F3%29%2Ax%2B2\" through the points (0,2) and (3,0)
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