document.write( "Question 1185618: Plywood contains minor imperfections that can be
\n" ); document.write( "repaired with small \"plugs.\" One customer will accept
\n" ); document.write( "plywood with a maximum of 3.5 plugs per sheet on
\n" ); document.write( "average. Suppose a shipment was sent to this customer,
\n" ); document.write( "and when the customer inspected two sheets at random,
\n" ); document.write( "10 plugged defects were counted. What is the
\n" ); document.write( "probability of observing 10 or more plugged defects if
\n" ); document.write( "in fact the 3.5 average per sheet is being satisfied?
\n" ); document.write( "Comment on what this probability implies about
\n" ); document.write( "whether you think the company is meeting the 3.5 per
\n" ); document.write( "sheet defect rate.
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Algebra.Com's Answer #816460 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
one would expect to see 7 plugs in two sheets.
\n" ); document.write( "Poisson parameter 7, see 10 or more
\n" ); document.write( "1-poisson cdf (7, 9)=0.1695
\n" ); document.write( "rough check is
\n" ); document.write( "p(10)=0.7100
\n" ); document.write( "p(11)=0.0452
\n" ); document.write( "p(12)=0.0263
\n" ); document.write( "p(13)=0.0142
\n" ); document.write( "p(14)=0.0071
\n" ); document.write( "p(15)=0.0033
\n" ); document.write( "that sum is 0.1660\r
\n" ); document.write( "\n" ); document.write( "If one uses a 5% level, the company is meeting standards.
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