document.write( "Question 1185622: Zodwa,the operations manager of a large production plant would like to estimate the mean amount of time a worker takes to assemble a new electronic component. Assume that the standard deviation of this assembly time 3.6 minutes.
\n" ); document.write( "(a) After observing 120 workers assembling similar devices, Zodwa noticed that their average time was 16.2 minutes. Construct a 92% confidence interval for the mean assembly time.\r
\n" ); document.write( "\n" ); document.write( "(b) How many workers should be involved in this study in order to have the mean assembly time estimated up to plus or minus 15 seconds with 92% confidence?
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Algebra.Com's Answer #816459 by Boreal(15235)\"\" \"About 
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92% half-interval is z(0.96)*3.6/sqrt(120)=1.75*3.6/sqrt(120)=0.575
\n" ); document.write( "the interval is (15.625 min, 16.775 min)
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\n" ); document.write( "error is the half-interval
\n" ); document.write( "so e=z(0.96)(sigma/sqrt(n)), error is 0.25 min
\n" ); document.write( "0.25=1.75*3.6/sqrt(n)
\n" ); document.write( "square both sides and move n over
\n" ); document.write( "0.0625n=39.69
\n" ); document.write( "n=635.04 or 636 people
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