document.write( "Question 1185566: A rectangle field has a premiere of 190 feet. The length is 5 feet more than 5 times the width. Find the dimensions \r
\n" ); document.write( "\n" ); document.write( "Length =\r
\n" ); document.write( "\n" ); document.write( "Width= \n" ); document.write( "

Algebra.Com's Answer #816381 by ikleyn(52804) $\"\"$ $\"About$

You can put this solution on YOUR website!
.
\n" ); document.write( "

\r\n" );
document.write( "width = x\r\n" );
document.write( "\r\n" );
document.write( "length = 5x+5\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "The equation\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "    x + (5x+5) = 190/2 \r\n" );
document.write( "\r\n" );
document.write( "    \r\n" );
document.write( "    6x + 5 = 95\r\n" );
document.write( "\r\n" );
document.write( "    6x = 95 - 5 = 90\r\n" );
document.write( "\r\n" );
document.write( "     x = 90/6 = 15.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "ANSWER.  The dimensions are  15 ft (width) and 5*15+5 = 80 ft (length).\r\n" );
document.write( "

\r
\n" ); document.write( "\n" ); document.write( "Solved.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );