document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=111773>Question 111773</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 2 in. more than twice its width.  If the perimeter of the rectangle is 52 in., find the width of the rectangle.  Solve using an algebraic equation.\r<BR>\n" );
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document.write( "Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #81637 by </B><A HREF=/tutors/aboutme.mpl?userid=elima><B>elima(1433)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=elima><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=81637\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 2 in. more than twice its width.  If the perimeter of the rectangle is 52 in., find the width of the rectangle.  Solve using an algebraic equation.<BR>\n" );
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document.write( "width = w<BR>\n" );
document.write( "length = 2w+2<BR>\n" );
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document.write( "2w+2+2w+2+w+w=52<BR>\n" );
document.write( "6w+4=52<BR>\n" );
document.write( "6w=48<BR>\n" );
document.write( "w=8<BR>\n" );
document.write( ":) </SPAN>\n" );
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