document.write( "Question 111890:
\n" ); document.write( "Could you please help me with this problem. Thank you in advance.\r
\n" ); document.write( "\n" ); document.write( "Three ex-teenagers find that the product of their ages is 26,390.
\n" ); document.write( "Find the sum of their ages.\r
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Algebra.Com's Answer #81636 by solver91311(24713)\"\" \"About 
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Your problem statement doesn't say, but I have to assume that the ages of the three people must be expressed in integers, otherwise there is no unique solution.\r
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\n" ); document.write( "\n" ); document.write( "Since they are ex-teenagers, you know they have to be at least 20 years old. But \"20%5E3=8000\" and that isn't large enough. \"30%5E3=27000\" which is just a little larger than the number we are looking for.\r
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\n" ); document.write( "\n" ); document.write( "Now if you start dividing 26,390 by 20, then 21, and so on, the first number that divides evenly is 26. \"26390%2F26=1015\", so we have a possible first number.\r
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\n" ); document.write( "\n" ); document.write( "So take the 1015 result and start dividing by 20, 21, etc. again, and you have to get all the way up to 29 before you obtain an even divisor.\r
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\n" ); document.write( "\n" ); document.write( "\"1015%2F29=35\"\r
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\n" ); document.write( "\n" ); document.write( "So that gives you the three ages, 26, 29, and 35. And the sum is 90
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