document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1185486>Question 1185486</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a metal bar weighing 180 kg is divided into two parts, so that the radio of the weight of the lighter part to that heavier part is 4:5. find the weight of each part<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #816314 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(52802)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=816314\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .\r<BR>\n" );
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document.write( "The parts weights are &nbsp;4x kg &nbsp;and &nbsp;5x kg; &nbsp;&nbsp;in total  4x + 5x = 9x kilograms.\r<BR>\n" );
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document.write( "Hence, &nbsp;from &nbsp;&nbsp;9x = 180 kg,  &nbsp;&nbsp;you have  &nbsp;&nbsp;x = 20 kg;  &nbsp;&nbsp;so the parts are &nbsp;80 kg &nbsp;and &nbsp;100 kg.\r<BR>\n" );
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document.write( "Solved.\r<BR>\n" );
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