document.write( "Question 1185483: Given the following, solve for the unknown quantity.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "1. Given:S4=120,r=3;find a1.
\n" ); document.write( "2. Given:S5=496,r=1/2;find a1.\r
\n" ); document.write( "\n" ); document.write( "sn=sum of the number
\n" ); document.write( "r=common ratio
\n" ); document.write( "a1=first term \n" ); document.write( "

Algebra.Com's Answer #816313 by ikleyn(52832) $\"\"$ $\"About$

You can put this solution on YOUR website!
.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " Part 1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "

\r\n" );
document.write( "a + 3a + 9a + 27a = 120\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "40a = 120\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "a = 120/40 = 3.    ANSWER\r\n" );
document.write( "

\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " Part 2\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "

\r\n" );
document.write( " +  +  +  +  = 496\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( " +  +  +  +  = 496\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( " = 496\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "a =  = 256.    ANSWER\r\n" );
document.write( "

\r
\n" ); document.write( "\n" ); document.write( "Solved.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );