document.write( "Question 1185479: The width of a rectangle is 4 less than twice its length. If the area of the rectangle is 120 cm2, what is the length of the diagonal? \n" ); document.write( "
Algebra.Com's Answer #816304 by josgarithmetic(39617)\"\" \"About 
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Width 2L-4
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\n" ); document.write( "\n" ); document.write( "\"L%282L-4%29=120\"
\n" ); document.write( "---
\n" ); document.write( "\"L%28L-2%29=60\"---------------\"60=4%2A15=5%2A12=6%2A10\"\r
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\n" ); document.write( "\n" ); document.write( "\"L%5E2-2L-60=0\"\r
\n" ); document.write( "\n" ); document.write( "\"L=%282%2B-+sqrt%284%2B4%2A60%29%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"L=%282%2B-+2sqrt%2861%29%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight_green%28L=1%2Bsqrt%2861%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28L%29%5E2%2B%282L-4%29%5E2=d%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28L%5E2%2B4L%5E2-16L%2B16%29\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight_green%28d=sqrt%285L%5E2-16L%2B16%29%29\"---------substitute here for L and evaluate d.\r
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