document.write( "Question 1185429: Could you please help me with this
\n" );
document.write( "How many ounces of 1% antifreeze solution must be added to 100 oz of 40% antifreeze solution to obtain a 16% antifreeze solution?\r
\n" );
document.write( "\n" );
document.write( "Thank you so much
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #816271 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "You have three responses showing formal algebraic solutions to your problem. All are valid.... \n" ); document.write( "If a formal algebraic solution is not required, here is a quick and easy way to solve this kind of problem (if the numbers are \"nice\") informally. \n" ); document.write( "You are starting with a 40% antifreeze solution and adding a 1% antifreeze solution until the mixture is 16% antifreeze. \n" ); document.write( "To model the problem, picture starting at 40% on a number line and \"walking\" towards 1%, stopping when you reach 16%. \n" ); document.write( "In doing that, you have walked 24/39 = 8/13 of the total distance. (40 to 1 is a difference of 39; 40 to 16 is a difference of 24; hence the fraction 24/39=8/13.) \n" ); document.write( "That means 8/13 of the mixture is the 1% antifreeze that you are adding. \n" ); document.write( "So the 100 ounces of 40% antifreeze you started with was 5/13 of the mixture; that means the 8/13 of the mixture that you added was 160 ounces. \n" ); document.write( "ANSWER: 160 ounces \n" ); document.write( " \n" ); document.write( " |