document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1185437>Question 1185437</A>: <I><SPAN STYLE=\"word-break: break-all;\"> donna invested part of her money at 8% and the remainder at 10%, if she invested P400,000 and received a total of P37,000 in interest, how much did she invest each rate?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #816270 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=816270\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "If a formal algebraic solution is not required, here is a quick an easy way to solve any 2-part mixture problem like this.<br><BR>\n" );
document.write( "(1) All P400,000 invested at 8% would yield P32000 interest; all at 10% would yield P40000 interest; the actual amount of interest was P37000.<br><BR>\n" );
document.write( "(2) Picture the three amounts 32000, 37000, and 40000 on a number line and observe/calculate that 37000 is 5000/8000 = 5/8 of the way from 32000 to 40000.<br><BR>\n" );
document.write( "(3)That means 5/8 of the total was invested at the higher rate.<br><BR>\n" );
document.write( "ANSWER: 5/8 of the P400,000, or P250,000, was invested at 10%; the other P150,000 at 8%<br><BR>\n" );
document.write( "CHECK: .10(250000)+.08(150000)=25000+12000=37000<br><BR>\n" );
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