document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1185422>Question 1185422</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I find the distance between and enter it as a radical or a decimal?\r<BR>\n" );
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document.write( "(-5,3) and (5,-3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #816245 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=816245\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the distance between (-5,3) and (5,-3) would be found by using the formula of:\r<BR>\n" );
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document.write( "length of a two dimensional line on a graph = square root of ((y2-y1)^2 + (x2-x1)^2)\r<BR>\n" );
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document.write( "you assing (x1,y1) to one of the points and (x2,y2) to the other point.\r<BR>\n" );
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document.write( "it doesn't matter which is assigned to which.\r<BR>\n" );
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document.write( "the length would be the same.\r<BR>\n" );
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document.write( "for example:\r<BR>\n" );
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document.write( "let(x1,y1) = (-5,3) and let (x2,y2) = (5,-3).\r<BR>\n" );
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document.write( "the length is equal to sqrt((x2-x1)^2 + (y2-y1)^2) = sqrt(5--5)^2 + (-3-3)^2) = sqrt(10^2 + (-6)^2) = sqrt(100 + 36) = sqrt(136).\r<BR>\n" );
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document.write( "let (x1,y1) = (5,-3) and let (x2,y2) = (-5,3).\r<BR>\n" );
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document.write( "the length is equal to sqrt((x2-x1)^2 + (y2-y1)^2) = sqrt(-5-5)^2 + (3--3)^2) = sqrt((-10)^2 + 6^2) = sqrt(100 + 36) = sqrt(136).\r<BR>\n" );
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document.write( "sqrt means the square root of.\r<BR>\n" );
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document.write( "if you look at the line on a graph, it would look like this.\r<BR>\n" );
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document.write( "the line itself is the hypotenuse of the right triangle formed.\r<BR>\n" );
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document.write( "the vertical leg is the length of (y2 - y1).\r<BR>\n" );
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document.write( "the horizontal leg is the length of (x2 - x1).\r<BR>\n" );
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document.write( "the pythagorean formula is used to get the length of the line itself.\r<BR>\n" );
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