document.write( "Question 111876: This one has me stumped on how to start. Given the formula A=p(1+r/t)^nt, answer the following problem: Find r given (A)=$95375, (p)=$65,750, and t=15 years with interest compounded monthly. Here's the formula I had after I plug every thing in to the formula: $95375 = $65750 (1+r/12)^(12*15 or 180)\r
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Algebra.Com's Answer #81621 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"95375=65750%281%2Br%2F12%29%5E180\" Start with the given equation \r
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\n" ); document.write( "\n" ); document.write( "\"95375%2F65750=cross%2865750%2F65750%29%281%2Br%2F12%29%5E180\" Divide both sides by 65750\r
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\n" ); document.write( "\n" ); document.write( "\"1.45057034220532=%281%2Br%2F12%29%5E180\" Divide\r
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\n" ); document.write( "\n" ); document.write( "\"root%28180%2C1.45057034220532%29=root%28180%2C%281%2Br%2F12%29%5E180%29\" Now to get rid of the exponent of 180, simply take the 180th root of both sides\r
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\n" ); document.write( "\n" ); document.write( "\"root%28180%2C1.45057034220532%29=1%2Br%2F12\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "\"1.0020685633009=1%2Br%2F12\" Take the 180th root of 1.45057034220532\r
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\n" ); document.write( "\n" ); document.write( "\"1.0020685633009-1=r%2F12\" Subtract 1 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"0.0020685633009=r%2F12\" Subtract\r
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\n" ); document.write( "\n" ); document.write( "\"0.0248227596108=r\" Multiply both sides by 12\r
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\n" ); document.write( "\n" ); document.write( "So the interest rate is approximately 0.0248227596108, or 2.482%
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