document.write( "Question 1185319: Wilma drove at an average speed of 45 mi/h from her home in City A to visit her sister in City B. She stayed in City B 10 hours, and on the trip back averaged 50 mi/h. She returned home 48 hours after leaving. How many miles is City A from City B? \n" ); document.write( "
Algebra.Com's Answer #816137 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "Wilma drove at an average speed of 45 mi/h from her home in City A to visit her sister in City B.
\n" ); document.write( "She stayed in City B 10 hours, and on the trip back averaged 50 mi/h.
\n" ); document.write( "She returned home 48 hours after leaving. How many miles is City A from City B?
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document.write( "Obviously, Wilma's travel time is  48 hours - 10 hours = 38 hours.\r\n" );
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document.write( "Let  d be the distance between the cities (the unknown value under the problem's question).\r\n" );
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document.write( "Then the time traveling from A to B is  \"d%2F45\"  hours;\r\n" );
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document.write( "     the time traveling back is  \"d%2F50\"  hours.\r\n" );
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document.write( "Total traveling time is 38 hours, giving this equation\r\n" );
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document.write( "    \"d%2F45\" + \"d%2F50\" = 38.    (1)\r\n" );
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document.write( "To solve it, multiply both sides by 450.  You will get\r\n" );
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document.write( "    10d + 9d = 38*450,\r\n" );
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document.write( "or\r\n" );
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document.write( "      19d     = 38*450,\r\n" );
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document.write( "        d     = \"%2838%2A450%29%2F19\" = 2*450 = 900.\r\n" );
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document.write( "ANSWER.  The distance between the cities A and B is 900 miles.\r\n" );
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document.write( "CHECK.   I will check the time equation (1):  \"900%2F45\" + \"900%2F50\" = 20 + 18 = 38  hours, total travel time.    ! Correct !\r\n" );
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