document.write( "Question 1185300: Solve each equation and to check for extraneous solutions\r
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Algebra.Com's Answer #816098 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"sqrt%282x%5E2+%2B+5x+%2B+6%29\"\"%22%22=%22%22\"\"x\"\r\n" );
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document.write( "We square both sides:\r\n" );
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document.write( "\"%28sqrt%282x%5E2+%2B+5x+%2B+6%29%29%5E2\"\"%22%22=%22%22\"\"%28x%29%5E2\"\r\n" );
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document.write( "When we square a square root we take away the square and the square root:\r\n" );
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document.write( "\"2x%5E2+%2B+5x+%2B+6\"\"%22%22=%22%22\"\"x%5E2\"\r\n" );
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document.write( "Subtract x2 from both sides:\r\n" );
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document.write( "\"x%5E2+%2B+5x+%2B+6\"\"%22%22=%22%22\"\"0\"\r\n" );
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document.write( "\"%28x%2B3%29%28x%2B2%29\"\"%22%22=%22%22\"\"0\"\r\n" );
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document.write( "Use the zero factor principle. Set each factor equal to 0:\r\n" );
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document.write( "x+3 = 0;   x+2 = 0\r\n" );
document.write( "  x = -3;    x = -2\r\n" );
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document.write( "We substitute those in the original equation to see if both are\r\n" );
document.write( "solutions to the original equations, or extraneous:\r\n" );
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document.write( "Substituting x = -3\r\n" );
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document.write( "\"sqrt%282%28-3%29%5E2+%2B+5%28-3%29+%2B+6%29\"\"%22%22=%22%22\"\"-3\"\r\n" );
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document.write( "\"sqrt%282%289%29+-+15+%2B+6%29\"\"%22%22=%22%22\"\"-3\"\r\n" );
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document.write( "\"sqrt%2818+-+15+%2B+6%29\"\"%22%22=%22%22\"\"-3\"\r\n" );
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document.write( "\"sqrt%289%29\"\"%22%22=%22%22\"\"-3\"\r\n" );
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document.write( "\"3\"\"%22%22=%22%22\"\"-3\"\r\n" );
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document.write( "That's false.  So -3 is an extraneous solution, so we discard it.\r\n" );
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document.write( "Substituting -2\r\n" );
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document.write( "\"sqrt%282%28-2%29%5E2+%2B+5%28-2%29+%2B+6%29\"\"%22%22=%22%22\"\"-2\"\r\n" );
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document.write( "\"sqrt%282%284%29+-+10+%2B+6%29\"\"%22%22=%22%22\"\"-2\"\r\n" );
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document.write( "\"sqrt%288+-+10+%2B+6%29\"\"%22%22=%22%22\"\"-2\"\r\n" );
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document.write( "\"sqrt%284%29\"\"%22%22=%22%22\"\"-2\"\r\n" );
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document.write( "\"2\"\"%22%22=%22%22\"\"-2\"\r\n" );
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document.write( "That's false.  So -2 is also an extraneous solution, so we discard it.\r\n" );
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document.write( "The equation has no solution.\r\n" );
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document.write( "Note: The symbol \"√(\" always means the POSITIVE square root. To indicate\r\n" );
document.write( "the negative square root, there must be a negative sign before it \"-√(\".\r\n" );
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document.write( "Edwin
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