document.write( "Question 1184550: A manufacturer knows that their items have a normally distributed length, with a mean of 5.5 inches, and standard deviation of 0.7 inches.\r
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document.write( "If 5 items are chosen at random, what is the probability that their mean length is less than 4.7 inches? (Give answer to 4 decimal places.) \n" );
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Algebra.Com's Answer #816089 by Theo(13342)![]() ![]() You can put this solution on YOUR website! the sample size is 5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if you follow this guide as to when to use the t-score or when to use the z-score, you will find that the use of the t-score is indicated in this problem.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "https://math.stackexchange.com/questions/1817980/how-to-know-when-to-use-t-value-or-z-value\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i'll do both to show you the difference.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the population mean is 5.5 inches. \n" ); document.write( "the population standard deviation is .7 inches.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the standard error = population standard deviation / square root of sample size = .7 / sqrt(5) = .31305.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the t-score is equal to (x - m) / s = (4.7 - 5.5) / .31305 = -2.5555.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the test t-score with 4 degrees of freedom give you an area of .0314687 to the left of that z-score.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your probability that the mean length is less than 4.7 inches is equal to .0315 rounded to 4 decimal places.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the z-score is also equal to -2.5555.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the probability of getting a z-score less than -2.5555 is equal to .0053.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's a reference on the relative shape of the t-score, depending on the degrees of freedom.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "https://www.statisticshowto.com/t-statistic/\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the t-score begins to look more like the z-score as the sample size goes up. \n" ); document.write( "at the lower end of sample sizes, the difference is more pronounced.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your solution in this problem is that the probability of getting a score less than 4.7 is equal to .0315 rounded to 4 decimal places.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this assumes use of the t-score.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if the use of the z-score is assumed, than the probability is .0053.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i would go with the assumption of t-score, unless otherwise instructed.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |