document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1185287>Question 1185287</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of three consecutive numbers is 63, find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #816087 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=816087\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x equal the first number, x + 1 equal the second number, x + 2 equal the third number.\r<BR>\n" );
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document.write( "you get:\r<BR>\n" );
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document.write( "x + (x + 1) + (x + 2) = 63\r<BR>\n" );
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document.write( "combine like terms to get 3x + 3 = 63\r<BR>\n" );
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document.write( "subtract 3 from both sides of the equation to get:\r<BR>\n" );
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document.write( "3x = 60\r<BR>\n" );
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document.write( "solve for x to get:\r<BR>\n" );
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document.write( "x = 60/3 = 20\r<BR>\n" );
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document.write( "the three numbers are 20, 21, and 22.\r<BR>\n" );
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document.write( "their sum is 63.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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