document.write( "Question 1185245: Mr Sam spent 1/4 of his money on 7 pens and 9 highlighters. Each pen cost 3 times as much as a highlighter. He bought some more pens with 2/3 of his remaining money. How many pens did Mr Sam buy altogether? \n" ); document.write( "
Algebra.Com's Answer #816070 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "He bought 7 pens and 9 highlighters; each pen cost 3 times as much as a highlighter. So what he spent was equivalent to 7(3)+9=30 highlighters, or 30/3=10 pens. \n" ); document.write( "He spent 1/4 of his money on that purchase, so he has 3/4 of his money left. When he spent 2/3 of his remaining money on more pens, he spent 2/3 of 3/4 of his original amount of money. \n" ); document.write( "2/3 of 3/4 of his original amount of money is 1/2 of his original money. That is twice as much as he spent on the first purchase (1/2 is twice as much as 1/4), so this second purchase was enough to buy 2*10=20 more pens. \n" ); document.write( "So the total number of pens he bought was 7+20 = 27. \n" ); document.write( "ANSWER: 27 \n" ); document.write( " \n" ); document.write( " |