document.write( "Question 1185249: Find the equation of the hyperbola, in general form, with vertices (±2,3) and a conjugate axis that measures 12 units. \n" ); document.write( "

Algebra.Com's Answer #816044 by Edwin McCravy(20060) $\"\"$ $\"About$

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document.write( "We plot the vertices (±2,3). Draw the transverse axis which is the line joining\r\n" );
document.write( "them. Then draw the conjugate 12 units long so that the transverse axis and\r\n" );
document.write( "conjugate axes are perpendicular bisectors of each other at the center, which\r\n" );
document.write( "is (0,3).\r\n" );
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document.write( "We draw the defining rectangle so that the two axes bisect it:\r\n" );
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document.write( "We draw and extend the two diagonals of the defining rectangle, which are the\r\n" );
document.write( "asymptotes of the hyperbola:\r\n" );
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document.write( "Now we sketch in the hyperbola:\r\n" );
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document.write( "The equation is\r\n" );
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document.write( "where a = half the transverse axis = 2\r\n" );
document.write( "and b = half the conjugate axis = 6\r\n" );
document.write( "and h = the x-coordinate of the center = 0\r\n" );
document.write( "and k = the y-coordinate of the center = 3\r\n" );
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document.write( "Which simplifies to:\r\n" );
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document.write( "Edwin

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