document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=111855>Question 111855</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/9780321437266/algebrahomeworkh>Beginning Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> A boat goes 6 miles per hour in still water. It takes as long to go 40 miles upstream as it does to go 80 miles downstream. Find the speed of the current. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #81604 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=81604\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 40/(6-C)=80/6+C) NOW CROSS MULTIPLY<BR>\n" );
document.write( "40(6+C)=80(6-C)<BR>\n" );
document.write( "240+40C=480-80C<BR>\n" );
document.write( "+40C+80C=480-240<BR>\n" );
document.write( "120C=240<BR>\n" );
document.write( "C=240/120<BR>\n" );
document.write( "C=2 MPH FOR THE CURRENT.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "40/(6-2)=80(6+2)<BR>\n" );
document.write( "40/4=80/8<BR>\n" );
document.write( "10=10<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );