document.write( "Question 1185229: Sam has purchased a $30,000 car for his business. The car depreciates 30% every year. Depreciate means the value of the car goes down by that percent each year. What will be the value of the car after the 5th year? Note: The car is 0 year old when purchased so the first year is the second entry in the sequence. \n" ); document.write( "

Algebra.Com's Answer #816023 by ikleyn(52781) $\"\"$ $\"About$

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\n" ); document.write( "Sam has purchased a $30,000 car for his business. The car depreciates 30% every year.
\n" ); document.write( "Depreciate means the value of the car goes down by that percent each year.
\n" ); document.write( "What will be the value of the car after the 5th year?
\n" ); document.write( "Note: The car is 0 year old when purchased so the first year is the second entry in the sequence.
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\n" ); document.write( "\n" ); document.write( "            I do not understand your question precisely.\r
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\n" ); document.write( "\n" ); document.write( "            After the 5th year, the 6th year follows.\r
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\n" ); document.write( "\n" ); document.write( "            So, I will give my answer for the 6-th year.\r
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document.write( "Every next year the value of the car is  100% - 30% = 70% = 0.7 of the previous year value.\r\n" );
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document.write( "0-th year value is $30,000.   n-th year value is  ,  n = 0, 1, 2, 3, . . . \r\n" );
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document.write( "  T    A    B    L    E\r\n" );
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document.write( "    year         value\r\n" );
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document.write( "  0-th year	30000.00\r\n" );
document.write( "  1-th year	21000.00\r\n" );
document.write( "  2-nd year	14700.00\r\n" );
document.write( "  3-rd year	10290.00\r\n" );
document.write( "  4-th year	 7203.00\r\n" );
document.write( "  5-th year	 5042.10\r\n" );
document.write( "  6-th year	 3529.47\r\n" );
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document.write( "6-th year value is   = 3529.47  dollars.      ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved and explained.\r
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