document.write( "Question 1185228: A virus reproduces by dividing into two, and after a certain growth period, it dividing into two again. As the virus continue to divine in two. How many viruses will be in system starting with a single virus AFTER 10 division? \n" ); document.write( "
Algebra.Com's Answer #816021 by ikleyn(52890) You can put this solution on YOUR website! . \n" ); document.write( "A virus reproduces by dividing into two, and after a certain growth period, it dividing into two again. \n" ); document.write( "As the virus continue to divine in two. How many viruses will be in system starting with a single virus AFTER 10 division? \n" ); document.write( "~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "After 1st division, there are 2 viruses.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "After 2nd division, there are 2*2 = 2^2 = 4 = 2^2 viruses.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "After 3rd division, there are 2*2^2 = 2*4 = 8 = 2^3 viruses.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "After 4th division, there are 2*2^3 = 2*8 = 16 = 2^4 viruses.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " . . . . and so on . . . . \r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "After 10th division, there are 2*2^9 = 2*512 = 1024 = 2^10 viruses. ANSWER\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |