document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1185208>Question 1185208</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The average dividend yield of a random sample of 25 JSE listed companies this year was found to be 14.5%, with a sample standard deviation of 3.4%. Assume that dividend yields are normally distributed.\r<BR>\n" );
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document.write( "(a) Calculate, with 90% confidence, the actual mean dividend yield of all JSE listed companies this year. Interpret finding and show all steps.<BR>\n" );
document.write( "(b) Calculate, with 95% confidence, the actual mean dividend yield of all JSE listed companies this year. Compare the interval with one calculated in 3.1.1 and show all the steps. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #815998 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=815998\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Half-interval for 90%t-interval is t(0.95,df=24)*s/ssqrt(n)<BR>\n" );
document.write( "=1.711*3.4/5=1.16%<BR>\n" );
document.write( "(13.34%, 15.66%)<BR>\n" );
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document.write( "For half-interval of 95% more confidence will be a wider interval: t(0.975, df=24)*s/sqrt(n)<BR>\n" );
document.write( "=2.064*3.4/5=1.40<BR>\n" );
document.write( "(13.1%, 15.9%)<BR>\n" );
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