document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=111856>Question 111856</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/9780321437266/algebrahomeworkh>Beginning Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> A small model plane travels 5 miles with the wind in the same amount of time as it takes to go 2 miles against the wind. The plane can travel 3 miles per hour in still air. Find the speed of the wind. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #81594 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=81594\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5/(3+W)=2/(3-W) NOW CROSS MULTIPLY.<BR>\n" );
document.write( "5(3-W)=2(3+W)<BR>\n" );
document.write( "15-5W=6+2W<BR>\n" );
document.write( "-5W-2W=6-15<BR>\n" );
document.write( "-7W=-9<BR>\n" );
document.write( "W=-9/-7<BR>\n" );
document.write( "W=1.29 MPH IS THE SPEED OF THE WIND.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "5/(3+1.29)=2/(3-1.29)<BR>\n" );
document.write( "5/4.29=2/1.71<BR>\n" );
document.write( "1.17=1.17<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );