document.write( "Question 1185090: A sales clerk in a departmental store claims that 45% of the shoppers entering the store leave without making a purchase. A random sample of 60 shoppers showed that 40 of them left without buying anything. Can we accept the clerk's claim at α=5% level of significance?\r
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Algebra.Com's Answer #815852 by Boreal(15235)\"\" \"About 
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p hat is 0.667 because 40/60 shoppers left without buying
\n" ); document.write( "Ho: p is =0.45
\n" ); document.write( "Ha: p is NE 0.45
\n" ); document.write( "alpha is 0.05 p{reject Ho|Ho true}
\n" ); document.write( "test stat is a z, 2-way 1-proportion test
\n" ); document.write( "reject Ho for |z|> 1.96
\n" ); document.write( "z=(p hat-p)/sqrt (p(1-p)/n)
\n" ); document.write( "=-0.667/sqrt (0.45*0.55/60)
\n" ); document.write( "=-0.217/0.0642
\n" ); document.write( "=-3.37
\n" ); document.write( "Reject Ho; the true proportion is not 0.45.
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