document.write( "Question 1185056: Clyde, Jeffrey and Geneross are three brothers. The sum of their ages five years ago is 13/25 of the
\n" ); document.write( "sum of their ages three years from now. If Geneross’s age is the same as the age of Clyde five years
\n" ); document.write( "ago and Clyde is two years older than Jeffrey. How old are they ten years from now?
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Algebra.Com's Answer #815797 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The difference between the sum of their ages 5 years ago and the sum of their ages 3 years from now is 3*8=24.

\n" ); document.write( "A mental path for the first part of the problem is to rewrite the given fraction 13/25 as an equivalent fraction in which the difference between numerator and denominator is 24. The difference between 13 and 25 is 12, so we can double numerator and denominator: 13/25 = 26/50.

\n" ); document.write( "So the sum of their ages 5 years ago was 26 and the sum of their ages 3 years from now is 50. That means the sum of their ages now is 41.

\n" ); document.write( "Geneross's age is the same as Clyde's age 5 years ago, so Geneross is 5 years younger than Clyde.

\n" ); document.write( "Clyde is 2 years older than Jeffrey, so Jeffrey is 2 years younger than Clyde.

\n" ); document.write( "x = Clyde
\n" ); document.write( "x-5 = Geneross
\n" ); document.write( "x-2 = Jeffrey

\n" ); document.write( "The sum of their current ages is 41:

\n" ); document.write( "\"x%2Bx-5%2Bx-2=41\"
\n" ); document.write( "\"3x-7=41\"
\n" ); document.write( "\"3x=48\"
\n" ); document.write( "\"x=16\"

\n" ); document.write( "Their current ages are
\n" ); document.write( "Clyde: x=16
\n" ); document.write( "Geneross: x-5=11
\n" ); document.write( "Jeffrey: x-2=14

\n" ); document.write( "ANSWER: Their ages 10 years from now will be
\n" ); document.write( "Clyde: 16+10=26
\n" ); document.write( "Geneross: 11+10=21
\n" ); document.write( "Jeffrey: 14+10=24

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