document.write( "Question 1185056: Clyde, Jeffrey and Geneross are three brothers. The sum of their ages five years ago is 13/25 of the
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document.write( "sum of their ages three years from now. If Geneross’s age is the same as the age of Clyde five years
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document.write( "ago and Clyde is two years older than Jeffrey. How old are they ten years from now? \n" );
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Algebra.Com's Answer #815797 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The difference between the sum of their ages 5 years ago and the sum of their ages 3 years from now is 3*8=24. \n" ); document.write( "A mental path for the first part of the problem is to rewrite the given fraction 13/25 as an equivalent fraction in which the difference between numerator and denominator is 24. The difference between 13 and 25 is 12, so we can double numerator and denominator: 13/25 = 26/50. \n" ); document.write( "So the sum of their ages 5 years ago was 26 and the sum of their ages 3 years from now is 50. That means the sum of their ages now is 41. \n" ); document.write( "Geneross's age is the same as Clyde's age 5 years ago, so Geneross is 5 years younger than Clyde. \n" ); document.write( "Clyde is 2 years older than Jeffrey, so Jeffrey is 2 years younger than Clyde. \n" ); document.write( "x = Clyde \n" ); document.write( "x-5 = Geneross \n" ); document.write( "x-2 = Jeffrey \n" ); document.write( "The sum of their current ages is 41: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Their current ages are \n" ); document.write( "Clyde: x=16 \n" ); document.write( "Geneross: x-5=11 \n" ); document.write( "Jeffrey: x-2=14 \n" ); document.write( "ANSWER: Their ages 10 years from now will be \n" ); document.write( "Clyde: 16+10=26 \n" ); document.write( "Geneross: 11+10=21 \n" ); document.write( "Jeffrey: 14+10=24 \n" ); document.write( " \n" ); document.write( " |