document.write( "Question 111795This question is from textbook Mathematics for the Trades
\n" ); document.write( ": B-18 Police Science Detectives investigating a crime find a bullet hole in a wall at a height of 7 ft 6 in from the door. The bullet passed through the wall at an angle of 34 degrees. If they assume that the gun was fired from a height of 4 ft above the floor, how far away from the wall was the gun when it was fired? I know the answer is 5 feet but how do I get it? Thanks \n" ); document.write( "

Algebra.Com's Answer #81576 by scott8148(6628) $\"\"$ $\"About$

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the difference between the height of the bullet hole (90 in) and the presumed height of the muzzle (48 in) is 42 in\r
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\n" ); document.write( "\n" ); document.write( "this is the length of the side of a right triangle that is opposite the 34° angle of elevetion of the muzzle
\n" ); document.write( "___ the right triangle is formed by the wall; the horizontal distance from the wall to the muzzle;
\n" ); document.write( "___ and the distance from the muzzle to the bullet hole\r
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\n" ); document.write( "\n" ); document.write( "using trigonometry; the side opposite the 34° angle, divided by the distance to the wall, is the tangent of the angle
\n" ); document.write( "___ so the distance to the wall is (42 in)/(tan 34) \n" ); document.write( "

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