document.write( "Question 111832: Find the area of the rectangle or square.\r
\n" ); document.write( "\n" ); document.write( "This shape is a square\r
\n" ); document.write( "\n" ); document.write( "The right side is = 1 1/3 yd\r
\n" ); document.write( "\n" ); document.write( "The bottom side is = 1 1/3 yd\r
\n" ); document.write( "\n" ); document.write( "Any help wtih this equation would be Greatly appreciated.
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Algebra.Com's Answer #81574 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"1%261%2F3\" Start with the given mixed number\r
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\n" ); document.write( "\n" ); document.write( " \"3%2A1=3\" Multiply the denominator 3 by the whole number 1 to get 3\r
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\n" ); document.write( "\n" ); document.write( " \"3%2B1=4\". Add 3 to the numerator 1 to get 4. This final result is the new numerator\r
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\n" ); document.write( "\n" ); document.write( " \"4%2F3\" Place the new numerator over the same denominator\r
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\n" ); document.write( "\n" ); document.write( " So the mixed number \"1%261%2F3\" is equivalent to the improper fraction \"4%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the base of \"4%2F3\" by the height of \"4%2F3\" (remember these are both equivalent to \"1%261%2F3\") to get\r
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\n" ); document.write( "\n" ); document.write( "\"%284%2F3%29%284%2F3%29=%284%2A4%29%2F%283%2A3%29=16%2F9\"\r
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\n" ); document.write( "\n" ); document.write( "So the area of the square is \"16%2F9\"
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