document.write( "Question 1185010: The Prior to medical visits, patients are asked to complete a self-administered medical history
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document.write( "form. The time it takes each patient to complete the form is approximately normally distributed,
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document.write( "with a mean of 12.4 minutes and a standard deviation of 2.1 minutes.
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document.write( "a) What proportion of patients completes the medical history form in 10 minutes or less?
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document.write( "b) What proportion of patients takes 20 minutes or more to complete the medical history form?
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document.write( "c) What is the 90th percentile of the time to complete the medical history form? \n" );
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Algebra.Com's Answer #815728 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! z=(x-mean)/sd \n" ); document.write( "a.z < (10-12.4)/2.1 \n" ); document.write( " =-1.14 \n" ); document.write( "that probability is 0.1271 \n" ); document.write( "- \n" ); document.write( "b. z > (20-12.4)/2.1 \n" ); document.write( "=7.6/2.1 \n" ); document.write( "=3.62 \n" ); document.write( "that probability is 0.00015 \n" ); document.write( "- \n" ); document.write( "90th percentile is z=+1.282 \n" ); document.write( "1.282=(x-12.4)/2.1 \n" ); document.write( "2.69=x-12.4 \n" ); document.write( "x=15.1 minutes \n" ); document.write( " \n" ); document.write( " |