document.write( "Question 1184987: Tom invests $7200 in two different accounts. The first account paid 6 %, the second account paid 12 % in interest. At the end of the first year he had earned $546 in interest. How much was in each account?\r
\n" ); document.write( "\n" ); document.write( "$ at 6 %\r
\n" ); document.write( "\n" ); document.write( "$ at 12 %
\n" ); document.write( "

Algebra.Com's Answer #815717 by JBnovelwriter(34)\"\" \"About 
You can put this solution on YOUR website!
\"7200=a%2Bb\"
\n" ); document.write( "
\n" ); document.write( "\"7200-a=b\"
\n" ); document.write( "\"0.06a%2B0.12b=546\"
\n" ); document.write( "\"0.06a%2B0.12%287200-a%29=546\" multiply in
\n" ); document.write( "\"0.06a%2B864-0.12a=546\" add the variables
\n" ); document.write( "\"-0.06a%2B864=546\" subtract 864
\n" ); document.write( "\"-0.06a=-318\" divide by -0.06
\n" ); document.write( "\"highlight%28a=5300%29\" take this and put in first equation
\n" ); document.write( "\"7200=a%2Bb\"
\n" ); document.write( "\"7200=5300%2Bb\"subtract 5300
\n" ); document.write( "\"highlight%281900=b%29\"\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );