document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1184982>Question 1184982</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi<BR>\n" );
document.write( "Luke can canoe at a speed of 3km per hour on a still lake. Luke took a canoe down a river at 2km per hour. <BR>\n" );
document.write( "He then returned upstream to his starting point.<BR>\n" );
document.write( "What was his average speed for the trip. \r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #815713 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=815713\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "His downstream speed will be 3+2=5km/h; his upstream speed will be 3-2=1km/h.<br><BR>\n" );
document.write( "The distances the two directions are the same; since his downstream speed is 5 times his upstream speed, his upstream trip will take 5 times as long as the downstream trip.<br><BR>\n" );
document.write( "His average speed is then the weighted average of his two speeds:<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%285%281%29%2B1%285%29%29%2F%285%2B1%29=10%2F6+=+5%2F3 ALIGN=MIDDLE  ALT=\"%285%281%29%2B1%285%29%29%2F%285%2B1%29=10%2F6+=+5%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "ANSWER: His average speed for the trip is (5/3)km/hr<br><BR>\n" );
document.write( " </SPAN>\n" );
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