document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=16721>Question 16721</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x to the second power minus 8x\r<BR>\n" );
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document.write( "x= -3\r<BR>\n" );
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document.write( "Thanks!<BR>\n" );
document.write( "Lainey </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #8157 by </B><A HREF=/tutors/aboutme.mpl?userid=41355><B>41355(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=41355><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=8157\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=-3<BR>\n" );
document.write( "x to the 2nd power= 9<BR>\n" );
document.write( "9-8x<BR>\n" );
document.write( "8x=8 multiplied by -3<BR>\n" );
document.write( "8 times -3=-24<BR>\n" );
document.write( "9--24<BR>\n" );
document.write( "9-24=-15 </SPAN>\n" );
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