document.write( "Question 1184982: Hi
\n" ); document.write( "Luke can canoe at a speed of 3km per hour on a still lake. Luke took a canoe down a river at 2km per hour.
\n" ); document.write( "He then returned upstream to his starting point.
\n" ); document.write( "What was his average speed for the trip. \r
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Algebra.Com's Answer #815690 by ikleyn(52777)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "Luke can canoe at a speed of 3km per hour on a still lake. Luke took a canoe down a river at 2km per hour.
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document.write( "Under given conditions, the effective rate canoeing downstream is  3 + 2 = 5 km/h,\r\n" );
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document.write( "while the effective rate canoeing upstream is  (3-2) = 1 km/h.\r\n" );
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document.write( "So, in this problem, you have a body moving with the rate of  u = 5 km/h  in one direction (downstream)\r\n" );
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document.write( "and moving with the rate of  v = 1 km/h in the opposite direction;\r\n" );
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document.write( "        the length of the trip is the same in both directions.\r\n" );
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document.write( "Under these conditions, the average rate is\r\n" );
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document.write( "    \"w%5Baverage%5D\" = \"%282%2Au%2Av%29%2F%28u%2Bv%29\" = \"%282%2A5%2A1%29%2F%285%2B1%29\" km/h = \"10%2F6\" km/h = \"5%2F3\" km/h = 1.6667 km/h.      ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved and thoroughly explained.\r
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