document.write( "Question 1184480: Marvin decided to rearrange his stamps in his stamp books, Book A, Book B and Book
\n" ); document.write( "C. First, he moved 2/9 of the stamps from Book B to Book C. Then, he moved 3/5 of the
\n" ); document.write( "remaining stamps from Book B to Book A. Next, he moved 1/3 of his stamps from Book
\n" ); document.write( "A to Book C. In the end, there were 240 fewer stamps in Book B than in Book A. Book
\n" ); document.write( "C had 460 more stamps than Book B and there were 600 stamps left in Book C. How
\n" ); document.write( "many more stamps were there in Book B than Book A at first?
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Algebra.Com's Answer #815630 by JBnovelwriter(34)\"\" \"About 
You can put this solution on YOUR website!
ABC
\n" ); document.write( "Make sure to understand that the original numbers for A, B, and C stay constant. any changes to the group you must include the constant.
\n" ); document.write( ".
\n" ); document.write( "First, he moved 2/9 of the stamps from Book B to Book C.
\n" ); document.write( "\"%282%2F9%29B%2BC\" =updated C book amount of stamps
\n" ); document.write( "Then, he moved 3/5 of the remaining stamps from Book B to Book A. (the remaining ould be what's left after subtracting 2/9ths of B.
\n" ); document.write( "\"%283%2F5%29%28B-%282B%2F9%29%29%2BA\"
\n" ); document.write( "\"%283%2F5%29%287B%2F9%29%2BA\" = updated A book amount of stamps
\n" ); document.write( "he moved 1/3 of his stamps from Book A to Book C
\n" ); document.write( "\"%28%281%2F3%29%28A%2B%28%283%2F5%29%287B%2F9%29%29%29%29%2B%28%282B%2F9%29%2BC%29\" = current C book amount of stamps
\n" ); document.write( "\"%282%2F3%29%28A%2B%28%283%2F5%29%287B%2F9%29%29%29\" is current A book
\n" ); document.write( "(In the end) this is very important terminology this now means everything following is the end results for each book not the original constants.
\n" ); document.write( "there were 240 fewer stamps in Book B than in Book A. 240 fewer than B = current state of B+240=current state of A.
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\n" ); document.write( "current Book C had 460 more stamps than current Book B. took current state of book C and set it equal to current B plus 460 more stamps.
\n" ); document.write( "\"%28%289B%2F9%29-%282B%2F9%29%29=%287B%2F9%29\"
\n" ); document.write( "\"%287B%2F9%29-%283%2F5%29%287B%2F9%29\" = Bs current book amount
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\n" ); document.write( "current C book=600 stamps left
\n" ); document.write( "\"%28%281%2F3%29%28A%2B%283%2F5%29%287B%2F9%29%29%29%2B%28%282B%2F9%29%2BC%29=600\"
\n" ); document.write( "so this means that current B book is = to 140=(600-460)
\n" ); document.write( "\"600=%287B%2F9%29-%283%2F5%29%287B%2F9%29%2B460\" solve for B, subtract 460 from each side
\n" ); document.write( "\"140=%287B%2F9%29-%283%2F5%29%287B%2F9%29\"multiply the fraction in
\n" ); document.write( "\"140=%287B%2F9%29-%2821B%2F45%29\" im not a fan of fractions so multiply both sides by 9
\n" ); document.write( "\"6300=%2835B%29-%2821B%29\"
\n" ); document.write( "\"6300=14B\"
\n" ); document.write( "\"highlight%28450=B%29\" We finally Found what B originally equaled. now we can use it in other equations to solve for the other books.
\n" ); document.write( ".
\n" ); document.write( "there were 240 fewer stamps in Book B than in Book A. 240 fewer than current A = current B +240= 140+240=380 is current A and current C is 600.
\n" ); document.write( "so now we have all the currents:
\n" ); document.write( "cA=380
\n" ); document.write( "cB=140
\n" ); document.write( "cC=600
\n" ); document.write( "so above is all the calculations you get from reading the word problem
\n" ); document.write( ".
\n" ); document.write( "you can now set each to the equations from above and use B=450 to find what C and A were at the start
\n" ); document.write( ".
\n" ); document.write( "cA=\"%282%2F3%29%28A%2B%28%283%2F5%29%287B%2F9%29%29%29\"
\n" ); document.write( "cC=\"%28%281%2F3%29%28A%2B%28%283%2F5%29%287B%2F9%29%29%29%29%2B%28%282B%2F9%29%2BC%29\"
\n" ); document.write( ".
\n" ); document.write( "\"%282%2F3%29%28A%2B%28%283%2F5%29%287B%2F9%29%29%29=380\"
\n" ); document.write( "B=450
\n" ); document.write( "solve for A
\n" ); document.write( "\"%282%2F3%29%28A%2B%28%283%2F5%29%287B%2F9%29%29%29=380\" multiply by 3
\n" ); document.write( "\"2A%2B%28%283%2F5%29%287B%2F9%29%29=1140\" multiply accross fractions
\n" ); document.write( "\"2A%2B%2835B%2F45%29=1140\" multiply by 45
\n" ); document.write( "\"45%282A%29%2B%2835B%29=51300\" substitute in the B=450
\n" ); document.write( "\"90A%2B%2835%28450%29%29=51300\"
\n" ); document.write( "\"90A%2B%2815750%29=51300\"
\n" ); document.write( "\"90A=35550\"
\n" ); document.write( "\"highlight%28A=395%29\"\r
\n" ); document.write( "\n" ); document.write( "\"A=395\"
\n" ); document.write( "\"B=450\"\r
\n" ); document.write( "\n" ); document.write( "How many more stamps were there in Book B than Book A at first?
\n" ); document.write( "\"B-A=x\"
\n" ); document.write( "\"450-395=x\"
\n" ); document.write( "\"highlight%2855%29=x\"\r
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\n" ); document.write( "\n" ); document.write( "sorry about all the updates after the post, realized I made a few mistakes and had to correct them. this was not an easy problem. It was quite difficult to keep everything straight. I got hung up on when it took a third of the current A book and forgot to change the current state of A to two-thirds of the updated A book. but it's all fixed now. :-)\r
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