document.write( "Question 1184480: Marvin decided to rearrange his stamps in his stamp books, Book A, Book B and Book
\n" );
document.write( "C. First, he moved 2/9 of the stamps from Book B to Book C. Then, he moved 3/5 of the
\n" );
document.write( "remaining stamps from Book B to Book A. Next, he moved 1/3 of his stamps from Book
\n" );
document.write( "A to Book C. In the end, there were 240 fewer stamps in Book B than in Book A. Book
\n" );
document.write( "C had 460 more stamps than Book B and there were 600 stamps left in Book C. How
\n" );
document.write( "many more stamps were there in Book B than Book A at first? \n" );
document.write( "
Algebra.Com's Answer #815630 by JBnovelwriter(34)![]() ![]() You can put this solution on YOUR website! ABC \n" ); document.write( "Make sure to understand that the original numbers for A, B, and C stay constant. any changes to the group you must include the constant. \n" ); document.write( ". \n" ); document.write( "First, he moved 2/9 of the stamps from Book B to Book C. \n" ); document.write( " \n" ); document.write( "Then, he moved 3/5 of the remaining stamps from Book B to Book A. (the remaining ould be what's left after subtracting 2/9ths of B. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "he moved 1/3 of his stamps from Book A to Book C \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "(In the end) this is very important terminology this now means everything following is the end results for each book not the original constants. \n" ); document.write( "there were 240 fewer stamps in Book B than in Book A. 240 fewer than B = current state of B+240=current state of A. \n" ); document.write( " \n" ); document.write( "current Book C had 460 more stamps than current Book B. took current state of book C and set it equal to current B plus 460 more stamps. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "current C book=600 stamps left \n" ); document.write( " \n" ); document.write( "so this means that current B book is = to 140=(600-460) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "there were 240 fewer stamps in Book B than in Book A. 240 fewer than current A = current B +240= 140+240=380 is current A and current C is 600. \n" ); document.write( "so now we have all the currents: \n" ); document.write( "cA=380 \n" ); document.write( "cB=140 \n" ); document.write( "cC=600 \n" ); document.write( "so above is all the calculations you get from reading the word problem \n" ); document.write( ". \n" ); document.write( "you can now set each to the equations from above and use B=450 to find what C and A were at the start \n" ); document.write( ". \n" ); document.write( "cA= \n" ); document.write( "cC= \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( "B=450 \n" ); document.write( "solve for A \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "How many more stamps were there in Book B than Book A at first? \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sorry about all the updates after the post, realized I made a few mistakes and had to correct them. this was not an easy problem. It was quite difficult to keep everything straight. I got hung up on when it took a third of the current A book and forgot to change the current state of A to two-thirds of the updated A book. but it's all fixed now. :-)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |