document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1184914>Question 1184914</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A foreman for an injection-molding firm admits that on 10% of his shifts, he forgets to shut off the injection<BR>\n" );
document.write( "machine on his line. This causes the machine to overheat, increasing the probability from 2%to 20% that a<BR>\n" );
document.write( "defective molding will be produced during the early morning run. What proportion of moldings from the early morning run is defective </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #815624 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=815624\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> without the overheating, the probability of a defective molding is 2%.\r<BR>\n" );
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document.write( "if the probability holds true, then 2% of the moldings are expected to be deficient on the normal runs.\r<BR>\n" );
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document.write( "on 10% of the runs, the machine is allowed to overheat, causing the probability of a defective molding to be 20%, rather an 2%.\r<BR>\n" );
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document.write( "if the probability holds true, then 20% of the moldings are expected to be deficient on those runs where the machines are allowed to overheat.\r<BR>\n" );
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document.write( "what i get rom this is:\r<BR>\n" );
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document.write( "the overall probability of defective moldings appears to be 90% at 2% and 10% at 20% = .9 * 2% + .10 * 20% = 3.8%.\r<BR>\n" );
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document.write( "assume 1000 shifts.<BR>\n" );
document.write( "90% are at 2% and 10% are at 20%.<BR>\n" );
document.write( "900 shifts are at 2% and 100 shifts are at 20%.<BR>\n" );
document.write( ".02 * 900 = 18 defectives in the normal runs.<BR>\n" );
document.write( ".20 * 100 = 20 defectives in the overheated runs.<BR>\n" );
document.write( "total defectives = 38.<BR>\n" );
document.write( "38 / 100 3.8%.\r<BR>\n" );
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document.write( "i think this is how you would look at this.<BR>\n" );
document.write( "give it a shot.<BR>\n" );
document.write( "see how you do.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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