document.write( "Question 1090632: If $1,000 is invested now, $1,500 two years from now, and $2,000 four years from not at an interest rate 6% compounded annually, what will be the total amount in 10 years?
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Algebra.Com's Answer #815623 by JBnovelwriter(34)\"\" \"About 
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end of year 1:
\n" ); document.write( "\"1000%2A0.06=60\"
\n" ); document.write( "\"1000%2B60=1060\"
\n" ); document.write( "end of year 2
\n" ); document.write( "\"1060%2A0.06=63.6\"
\n" ); document.write( "\"1060%2B63.6=1123.60\"
\n" ); document.write( "\"1123.60%2B1500=2623.60\"
\n" ); document.write( "end of year 3
\n" ); document.write( "\"2623.60%2A0.06=157.416\"
\n" ); document.write( "\"2623.60%2B157.416=2781.016\"
\n" ); document.write( "end of year 4
\n" ); document.write( "\"2781.016%2A0.06=166.8609\"
\n" ); document.write( "\"2781.016%2B166.8609=2947.87696\"
\n" ); document.write( "\"2947.87696%2B2000=4947.87696\"
\n" ); document.write( "end of year 5
\n" ); document.write( "\"4947.87696%2A0.06=296.87261\"
\n" ); document.write( "\"4947.87696%2B296.87261=5244.74958\"
\n" ); document.write( "end of year 6
\n" ); document.write( "\"5244.74958%2A0.06=314.68497\"
\n" ); document.write( "\"5244.74958%2B314.68497=5559.43455\"
\n" ); document.write( "end of year 7
\n" ); document.write( "\"5559.43455%2A0.06=333.56607\"
\n" ); document.write( "\"5559.43455%2B333.56607=5893.00067\"
\n" ); document.write( "end of year 8
\n" ); document.write( "\"5893.00067%2A0.06=353.58004\"
\n" ); document.write( "\"5893.00067%2B353.58004=6246.58071\"
\n" ); document.write( "end of year 9
\n" ); document.write( "\"6246.58071%2A0.06=374.79484\"
\n" ); document.write( "\"6246.58071%2B374.79484=6621.37555\"
\n" ); document.write( "end of year 10
\n" ); document.write( "\"6621.37555%2A0.06=397.28253\"
\n" ); document.write( "\"6621.37555%2B397.28253=highlight%287018.65808%29\" \n" ); document.write( "
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