document.write( "Question 1184922: Gary bought 3/5 as many apples as oranges from the supermarket. He gave away 6 apples and 26 oranges. He then had 3/4 as many apples left as oranges. How many apples and oranges did Gary buy altogether? \n" ); document.write( "
Algebra.Com's Answer #815595 by JBnovelwriter(34)\"\" \"About 
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a= apples b=oranges
\n" ); document.write( "\"%283%2F5%29b=a\"
\n" ); document.write( "\"a-6=%283%2F4%29%28b-26%29\"
\n" ); document.write( "You have what a equals so replace a in 2nd equation
\n" ); document.write( "\"%283%2F5%29b-6=%283%2F4%29%28b-26%29\"
\n" ); document.write( "Now we start solving for b
\n" ); document.write( "Go ahead and do the reciprocal of 3/4 so times by 4/3 to each side
\n" ); document.write( "\"%284%2F3%29%283%2F5%29b-%284%2F3%29%286%29=b-26\" left side 3s cancel and the 6 becomes a 2
\n" ); document.write( "\"%284%2F5%29b-8=+b-26\" lets get rid of the 26 to isolate one variable add 26 to each side.
\n" ); document.write( "\"%284%2F5%29b%2B18=b\" lets get rid of the other fraction so multiply both sides by 5
\n" ); document.write( "\"4b%2B90=5b\" subtract 4b from both sides
\n" ); document.write( "\"90=b\" now take this value and put in the first equation
\n" ); document.write( "\"%283%2F5%29b=a\"
\n" ); document.write( "\"%283%2F5%29%2890%29=a\" the 90 can be reduced by the 5 to 18 (18*5=90) and (3*18=54)
\n" ); document.write( "\"54=a\"
\n" ); document.write( "54 apples 90 oranges
\n" ); document.write( "Total of 144 fruits\r
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