document.write( "Question 1184908: If the breadth of a rectangle is decreased by 20% and the length increased by 10%, a square of area 1936m^2 is obtained what is the area of the rectangle in square metres.
\n" ); document.write( "A) 2200
\n" ); document.write( "B)3500
\n" ); document.write( "C)2250
\n" ); document.write( "D)1450
\n" ); document.write( "E)4506
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Algebra.Com's Answer #815566 by Theo(13342)\"\" \"About 
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i get selection A = 2200 square meters.\r
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\n" ); document.write( "\n" ); document.write( "here's why.\r
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\n" ); document.write( "\n" ); document.write( "if you take 80% of the width and 110% of the length, you get a square with an area of 1936 square meters.\r
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\n" ); document.write( "\n" ); document.write( "the square root of 1936 = 44.\r
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\n" ); document.write( "\n" ); document.write( "80% of your width must be equal to 44.
\n" ); document.write( "110% of your length must be equal to 44.\r
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\n" ); document.write( "\n" ); document.write( "if 80% of your width is equal to 44, then your original width must have been 44 / .8 = 55.\r
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\n" ); document.write( "\n" ); document.write( "if 110% of your length is equal to 44, then your original length must have been 44 / 1.1 = 40\r
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\n" ); document.write( "\n" ); document.write( "your original length is 40 and your original width is 55.
\n" ); document.write( "your original area must be 40 * 55 = 2200.\r
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