document.write( "Question 1184690: A teenager has $10,000 invested in a checking
\n" ); document.write( "account paying 2.5% per year and a savings
\n" ); document.write( "account paying 6.5% per year. The total
\n" ); document.write( "interest earned in the two accounts at the end
\n" ); document.write( "of the year was equivalent to an annual rate of
\n" ); document.write( "6% on the entire $10,000. How much was
\n" ); document.write( "invested in each account? \n" ); document.write( "

Algebra.Com's Answer #815544 by math_helper(2461) $\"\"$ $\"About$

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document.write( "Let x = amount invested at 2.5%
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document.write( "then  10000-x = amount invested at 6.5%\r
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document.write( "(0.025)x + (0.065)(10000-x) = (0.06)(10000)\r
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document.write( "Solve the above for x:
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document.write( "x =   (= amount invested at 2.5%)
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document.write( "10000-x =  (= amount invested at 6.5%)\r
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document.write( "Check:
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document.write( " 0.025(1250) + 0.065(8750) = 600 = 0.06(10000)  \n" );
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