document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1184883>Question 1184883</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has three different acid solutions. The first acid solution contains 25 % acid, the second contains 40 % and the third contains 85 % . He wants to use all three solutions to obtain a mixture of 135 liters containing 35 % acid, using 2 times as much of the 85 % solution as the 40 % solution. How many liters of each solution should be used?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #815542 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=815542\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The first acid solution contains 25 % acid, --x liters<BR>\n" );
document.write( "the second contains 40 % -- y liters<BR>\n" );
document.write( "and the third contains 85 % -- z liters<BR>\n" );
document.write( "x+y+z =135-------(1)\r<BR>\n" );
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document.write( "Quantities used Concentration<BR>\n" );
document.write( "25%x + 40%y + 85% z = 35% (x+y+z)\r<BR>\n" );
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document.write( "25x + 40y +85z = 35x+35y+35z<BR>\n" );
document.write( "50z +5y-10x =0    --------(2)\r<BR>\n" );
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document.write( "z=2y------------------(3)\r<BR>\n" );
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document.write( "substitute z=2y <BR>\n" );
document.write( "in (1) we get x+3y =135<BR>\n" );
document.write( "in (2) we get 105y-10x= =0<BR>\n" );
document.write( "10x=105y<BR>\n" );
document.write( "x=10.5 y\r<BR>\n" );
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document.write( "x+3y =135<BR>\n" );
document.write( "substitute x=10.5 y<BR>\n" );
document.write( "13.5y =135<BR>\n" );
document.write( "y =10 liters\r<BR>\n" );
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document.write( "z=2y<BR>\n" );
document.write( "z = 20 liters<BR>\n" );
document.write( "x =105 liters\r<BR>\n" );
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document.write( "The first acid solution 25% , --105 liters<BR>\n" );
document.write( "the second contains 40 % -- 10 liters<BR>\n" );
document.write( "and the third contains 85 % -- 20 liters\r<BR>\n" );
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