document.write( "Question 1184881: A mixture of 22% disinfectant solution is to be made from 15% and 25% disinfectant solutions. How much of each solution should be used if 20 gallons of the 22% solution are needed?\r
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document.write( "I tried .25x+.15(20-x)=.22*20
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document.write( "as my equation, and got x =14. so, you would need 6 gallons of 25 and 14 of 15 but i got it wrong. \n" );
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Algebra.Com's Answer #815537 by ikleyn(52800)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "You correctly obtained x = 14 from your equation as a solution,\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "but INCORRECTLY interpreted it . . . . \r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "These 14 gallons is the amount of the 25% solution.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "So, the answer is: 14 gallons of the 25% solution, and the rest, 20-14 = 6 gallons is the amount of the 15% solution.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "CHECK for the concentration :\r \n" ); document.write( "\n" ); document.write( "Solved and explained.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |